document.write( "Question 1199651: The sum of the first four terms of a linear sequence A.p is 26 and that of the next four term is 74. find the value of the first term ,the common difference \n" ); document.write( "
Algebra.Com's Answer #833618 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Each number in the second sub-sequence of 4 terms is equal to the corresponding number in the first sub-sequence of 4 terms, plus the common difference 4 times. \n" ); document.write( "So the sum of the 4 terms of the second sub-sequence is 4(4) = 16 times the common difference. \n" ); document.write( "The difference between the sums of the two sub-sequences is 74-26 = 48: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The common difference for the sequence is 3. \n" ); document.write( "The first term of the sequence is a; the fourth term is a+3d = a+9. \n" ); document.write( "The sum of the first four terms of the sequence is 4 times the average of the first and fourth terms; that sum is 26: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWERS: first term a=2; common difference 3 \n" ); document.write( " \n" ); document.write( " |