document.write( "Question 1199651: The sum of the first four terms of a linear sequence A.p is 26 and that of the next four term is 74. find the value of the first term ,the common difference \n" ); document.write( "
Algebra.Com's Answer #833618 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Each number in the second sub-sequence of 4 terms is equal to the corresponding number in the first sub-sequence of 4 terms, plus the common difference 4 times.

\n" ); document.write( "So the sum of the 4 terms of the second sub-sequence is 4(4) = 16 times the common difference.

\n" ); document.write( "The difference between the sums of the two sub-sequences is 74-26 = 48:

\n" ); document.write( "\"16d=48\"
\n" ); document.write( "\"d=3\"

\n" ); document.write( "The common difference for the sequence is 3.

\n" ); document.write( "The first term of the sequence is a; the fourth term is a+3d = a+9.

\n" ); document.write( "The sum of the first four terms of the sequence is 4 times the average of the first and fourth terms; that sum is 26:

\n" ); document.write( "\"4%28%28a%2Ba%2B9%29%2F2%29=26\"
\n" ); document.write( "\"4%282a%2B9%29=52\"
\n" ); document.write( "\"2a%2B9=13\"
\n" ); document.write( "\"2a=4\"
\n" ); document.write( "\"a=2\"

\n" ); document.write( "ANSWERS: first term a=2; common difference 3

\n" ); document.write( "
\n" ); document.write( "
\n" );