document.write( "Question 1199663: In the rectangle ABCD, what is the distance from point E to point F, in mm?
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Algebra.Com's Answer #833617 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "(1)  The diagonal |BD| = \"sqrt%2824%5E2%2B7%5E2%29\" = 25 mm.\r\n" );
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document.write( "(2)  From the area consideration, you have for the area of the triangle BCD\r\n" );
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document.write( "         \"%281%2F2%29%2A24%2A7\" = \"%281%2F2%29%2Aabs%28BD%29%2Aabs%28FC%29\"\r\n" );
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document.write( "     or\r\n" );
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document.write( "         24*7 = 25*|FC|,  which gives  |FC| = \"%2824%2A7%29%2F25\" mm.\r\n" );
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document.write( "(3)  Then from triangle CDF,  |FD| = \"sqrt%287%5E2+-+%28%2824%2A7%29%2F25%29%29%5E2%29\" = \r\n" );
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document.write( "                                   = \"sqrt%28%287%5E2%2A25%5E2-7%5E2%2A24%5E2%29%2F25%5E2%29\" = \"sqrt%28%287%5E2%2A49%29%2F25%5E2%29\" = \"49%2F25\" = 1.96 mm.\r\n" );
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document.write( "(4)  Thus  |FD| = |BE| = 1.96 mm.\r\n" );
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document.write( "(5)  Hence,  |EF| = 25 - 2*1.96 = 21.08 mm = 21 \"8%2F100\" mm = 21 \"2%2F25\" mm.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "It can be solved in different way, using similarity of triangles.\r
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\n" ); document.write( "\n" ); document.write( "But in my solution, there are so many nice numbers on the way, that I decided to show you THIS version.\r
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