document.write( "Question 1199661: If one angle of a triangle is 30 degrees more than twice another, and the third angle is equal to the sum of the first two angles, find the measures of each angle. (Hint: the three angles in a triangle add up to 180 degrees) \n" ); document.write( "

Algebra.Com's Answer #833611 by ikleyn(52832) $\"\"$ $\"About$

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document.write( "x = angular measure of the \"another\" angle\r\n" );
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document.write( "2x+30 is that of the \"one\" angle\r\n" );
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document.write( "x + (2x+30) = 3x+30 is that of the third angle.\r\n" );
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document.write( "The basic equation for the sum of the three angles is\r\n" );
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document.write( "    x + (2x+30) + (3x+30) = 180.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    6x = 180 - 30 - 30 = 120 degrees.\r\n" );
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document.write( "     x                 = 120/6 = 20 degrees.\r\n" );
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document.write( "ANSWER.  The angles are 20 degs, 2*20+30 = 70 degs and 3*20+30 = 90 degs.\r\n" );
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document.write( "CHECK.  20 + 70 + 90 = 180 degs.   ! correct !\r\n" );
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