document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199590>Question 1199590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "Box A contains $1 coins box B contains 50 cent coins and box C contains 20cent coins. A  has 5 times as many coins as C. B has 12 fewer than A. C has half the number in B. How much money is in box A. \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833524 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A has more coins than C; B has fewer than A; and C has half as many as B.  Since the number in C is smallest....<br><BR>\n" );
document.write( "Let x = # of coins in C<BR>\n" );
document.write( "Then 2x = # of coins in B<BR>\n" );
document.write( "And 5x = # of coins in A<br><BR>\n" );
document.write( "The number of coins in B is 12 less than the number in A:<br><BR>\n" );
document.write( "2x = 5x-12<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "x = 4<br><BR>\n" );
document.write( "The number of coins in A is 5x = 5*4 = 20.<br><BR>\n" );
document.write( "ANSWER: 20*($1) = $20<br><BR>\n" );
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