document.write( "Question 1199568: Bob threw a ball upward at a velocity of 10 m/s while standing on the roof of a building that was 12 m high. What was the height of the ball after 2 seconds?\r
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document.write( "I am using h= -16t^2 +10t + 12\r
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document.write( "if I substitute 2 for t, I get -32. How can I get negative time? \n" );
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Algebra.Com's Answer #833504 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! First of all, you are solving for the height of the ball, not the time. \n" ); document.write( "Secondly, you are mixing English units and metric units. We are given the speed \n" ); document.write( "and height in m/s and m, but in the formula h(t) = h0 + v0*t - 1/2g*t^2, you are \n" ); document.write( "using g = 32 ft/s^2 instead of g = 9.8 m/s^2. Make the substitution and you will \n" ); document.write( "get a sensible answer for the height. \n" ); document.write( " |