document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199514>Question 1199514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The roots of the equation x^2+2px+q differ by 1.show that p^2=q+1/4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833438 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the quadratic formula, the two roots are (-2p + sqrt(4p^2-4q))/2 and<BR>\n" );
document.write( "(-2p - sqrt(4p^2-4q))/2. Simplifying and setting the difference equal to 1 we get:<BR>\n" );
document.write( "-p + sqrt(p^2-q) - (-p - sqrt(p^2-q)) = 1<BR>\n" );
document.write( "2*sqrt(p^2-q) = 1 -> p^2-q = 1/4 </SPAN>\n" );
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