document.write( "Question 1199504: A school is selling tickets to a talent show. On the first day of sales they sold 1 adult ticket and 6 student tickets for a total of $60. On the last day of sales, they sold 6 adult tickets and 15 student tickets for a total of $192. What was the price of the adult ticket?
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Algebra.Com's Answer #833429 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Informally, using logical reasoning and mental arithmetic....

\n" ); document.write( "Since 1 adult ticket and 6 student tickets cost $60, 6 adult tickets and 36 student tickets would cost $360.
\n" ); document.write( "Comparing that to the $192 cost of 6 adult tickets and 15 student tickets, we see that the 36-15=21 additional student tickets cost an additional $360-$192 = $168; so the cost of each student ticket is $168/21 = $8.
\n" ); document.write( "So on the first day the 6 student tickets cost 6($8) = $48, which means the 1 adult ticket cost $60-$48 = $12.

\n" ); document.write( "ANSWER: The price of an adult ticket was $12.

\n" ); document.write( "The exact same thing, using formal algebra....
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document.write( "x+6y = 60       given\r\n" );
document.write( "6x+36y = 360    multiply by 6\r\n" );
document.write( "6x+15y = 192    given\r\n" );
document.write( "21y = 168       the difference between the two equations\r\n" );
document.write( "y = 8           solve for y\r\n" );
document.write( "x+6(8) = 60     solve for x\r\n" );
document.write( "x+48 = 60\r\n" );
document.write( "x = 12

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