document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114572>Question 114572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> equation of the line through points (6,-2) and perpendicular to the line 2x-3y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83342 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST YOU NEED TO FIND THE SLOPE OF THE GIVEN LINE.<BR>\n" );
document.write( "Y=mX+b WHERE (m)=SLOPE.<BR>\n" );
document.write( "2X-3Y=-7<BR>\n" );
document.write( "-3Y=-2X-7<BR>\n" );
document.write( "Y=-2X/-3-7/-3<BR>\n" );
document.write( "Y=2X/3+7/3 THUS THIS SLOPE=2/3.<BR>\n" );
document.write( "A PERPENDICULAR LINE WOULD HAVE A SLOPE = TO THE NEGATIVE RECIPRICAL OF THIS SLOPE.<BR>\n" );
document.write( "THUS THE REQUIRED SLOPE=-3/2 FOR THE PERPENDICULAR LINE.<BR>\n" );
document.write( "USING THE LINE FORMULA Y=mX+b & SUBSTITUTING THE POINT (6,-2) & THE SLOPE=-3/2 YOU NEED TO SOLVE FOR b THE Y INTERCEPT.<BR>\n" );
document.write( "-2=-3/2*6+b<BR>\n" );
document.write( "-2=-18/2+b<BR>\n" );
document.write( "b=-2+9<BR>\n" );
document.write( "b=7<BR>\n" );
document.write( "SO THE LINE EQUATION IS:<BR>\n" );
document.write( "Y=-3X/2+7  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );