document.write( "Question 114495This question is from textbook
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document.write( "The length of a rectangle is 10 meters more than one-half the width. If the perimeter is 44 meters, what are the length and width? \n" );
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Algebra.Com's Answer #83340 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Perimeter(P) of a rectangle equals the two times the Length(L) plus two times the Width(W) or:\r \n" ); document.write( "\n" ); document.write( "P=2L+2W\r \n" ); document.write( "\n" ); document.write( "Let W=the width \n" ); document.write( "W/2=one half the width \n" ); document.write( "((W/2)+10)= 10 meters more than half the width=L\r \n" ); document.write( "\n" ); document.write( "So:\r \n" ); document.write( "\n" ); document.write( "P=44=2((W/2)+10)+2W get rid of parens and simplify \n" ); document.write( "44=W+20+2W subtract 20 from both sides\r \n" ); document.write( "\n" ); document.write( "44-20=W+20-20+2W collect like terms\r \n" ); document.write( "\n" ); document.write( "24=3W divide both sides by 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W=8 units-----------------width\r \n" ); document.write( "\n" ); document.write( "(W/2)+10=(8/2)+10=4+10=14 units---------------length\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "4+10=14 \n" ); document.write( "14=14 \n" ); document.write( "2*8+2*14=44 \n" ); document.write( "16+28=44 \n" ); document.write( "44=44\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |