document.write( "Question 114504: The sum of two numbers is 39 and their difference is 7. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #83334 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "THERE ARE TWO WAYS (MAYBE MORE) TO WORK THIS:\r
\n" ); document.write( "\n" ); document.write( "LETS DO THE EASY WAY FIRST, THEN I WILL SET UP THE HARD WAY AND YOU CAN FINISH IT.\r
\n" ); document.write( "\n" ); document.write( "Let x=one number
\n" ); document.write( "Then 39-x=the other number\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:\r
\n" ); document.write( "\n" ); document.write( "(39-x)-x=7 get rid of parens (distributive law)\r
\n" ); document.write( "\n" ); document.write( "39-x-x=7 subtract 39 from both sides\r
\n" ); document.write( "\n" ); document.write( "39-39-x-x=7-39 collect like terms\r
\n" ); document.write( "\n" ); document.write( "-2x=-32 divide both sides by -2
\n" ); document.write( "x=16-------------------one number\r
\n" ); document.write( "\n" ); document.write( "39-x=39-16=23------------the other number\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "their difference IS 7 and their sum IS 39\r
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\n" ); document.write( "\n" ); document.write( "THE HARD WAY:
\n" ); document.write( "Let x=one number
\n" ); document.write( "And y=the other number\r
\n" ); document.write( "\n" ); document.write( "x+y=39----------------------------eq1
\n" ); document.write( "x-y=7--------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "substitute x=39-y from eq1 into eq2 and we get\r
\n" ); document.write( "\n" ); document.write( "x-(39-x)=7 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "x-39+x=7 add 39 to both sides
\n" ); document.write( "x-39+39+x=7+39 collect like terms\r
\n" ); document.write( "\n" ); document.write( "2x=46\r
\n" ); document.write( "\n" ); document.write( "Now you finish this one\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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