document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114554>Question 114554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill drove from Ajax to Bixby at an average speed of 50mi/h.  On the way back, he drove at 60mi/h.  The total trip took 4 2/3 hours of driving time.  Find the distance between the two cities. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83333 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50T=60(14/3-T)<BR>\n" );
document.write( "50T=20*14-60T<BR>\n" );
document.write( "50T+60T=280<BR>\n" );
document.write( "110T=280<BR>\n" );
document.write( "T=280/110<BR>\n" );
document.write( "T=2 60/110 OR 2 6/10 HOURS FOR THE 50 MPH TRIP.<BR>\n" );
document.write( "4 2/3-2 6/10<BR>\n" );
document.write( "14/3-26/10<BR>\n" );
document.write( "(14*10-3*26)/30<BR>\n" );
document.write( "(140-78)/30<BR>\n" );
document.write( "62/30=2 1/15 HOURS FOR THE 60 MPH TRIP.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2 6/10+2 1/15<BR>\n" );
document.write( "26/10+31/15<BR>\n" );
document.write( "(26*15+31*10)/150<BR>\n" );
document.write( "(390+310)/150<BR>\n" );
document.write( "700/150= 4 2/3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );