document.write( "Question 1199434: Find three consecutive even integers such that the sum of twice the first and three times the third is fourteen more than four times the second. \n" ); document.write( "
Algebra.Com's Answer #833315 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "A = 1st number
\n" ); document.write( "B = 2nd number
\n" ); document.write( "C = 3rd number
\n" ); document.write( "Each item is a consecutive even integer.
\n" ); document.write( "Eg: 4,6,8\r
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\n" ); document.write( "\n" ); document.write( "A = x
\n" ); document.write( "B = x+2
\n" ); document.write( "C = x+4
\n" ); document.write( "where x is an even integer\r
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\n" ); document.write( "\n" ); document.write( "The phrase \"sum of twice the first and three times the third is fourteen more than four times the second\" translates to
\n" ); document.write( "2A+3C = 4B+14\r
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\n" ); document.write( "\n" ); document.write( "Apply substitution and solve for x.
\n" ); document.write( "2A+3C = 4B+14
\n" ); document.write( "2x+3(x+4) = 4(x+2)+14
\n" ); document.write( "2x+3x+12 = 4x+8+14
\n" ); document.write( "5x+12 = 4x+22
\n" ); document.write( "5x-4x = 22-12
\n" ); document.write( "x = 10\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "A = x = 10
\n" ); document.write( "B = x+2 = 10+2 = 12
\n" ); document.write( "C = x+4 = 10+4 = 14\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "2A+3C = 4B+14
\n" ); document.write( "2*10+3*14 = 4*12+14
\n" ); document.write( "20+42 = 48+14
\n" ); document.write( "62 = 62
\n" ); document.write( "The answers are confirmed.\r
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\n" ); document.write( "\n" ); document.write( "----------------------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "10,12,14
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