document.write( "Question 114555: If ben invests $4000 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that the interest he recieved each year is 4 1/2% of the total amount invested? \n" ); document.write( "
Algebra.Com's Answer #83331 by checkley71(8403)\"\" \"About 
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.04*4000+.055*X=.045(4000+X)
\n" ); document.write( "160+.055X=180+.045
\n" ); document.write( ".055X-.045X=180-160
\n" ); document.write( ".01X=20
\n" ); document.write( "X=20/.01
\n" ); document.write( "X=2000 AMOUNT INVESTED @ 5.5%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".04*4000+.055*2000=.045(4000+2000)
\n" ); document.write( "160+110=.045*6000
\n" ); document.write( "270=270
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