document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114556>Question 114556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular parcel of land is 70ft longer than it is wide.  Each diagonal between opposite corbers is 130ft.  What are the demensions of the parcel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83329 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> GIVEN THAT THE DIAGONALS ARE EACH(=) THEN THESE DIAGONALS FOR A RIGHT TRIANGLE.<BR>\n" );
document.write( "THUS:<BR>\n" );
document.write( "X^2+(X+70)^2=130^2<BR>\n" );
document.write( "X^2+X^2+140X+4900=16900<BR>\n" );
document.write( "2X^2+140X+4900-16900=0<BR>\n" );
document.write( "2X^2+140X-12000=0<BR>\n" );
document.write( "2(X^2+70-6000)=0<BR>\n" );
document.write( "2(X-50)(X+120)=0<BR>\n" );
document.write( "X-50=0<BR>\n" );
document.write( "X=50 FEET IS THE ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "50+70=120 FEET FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "50^2+120^2=130^2<BR>\n" );
document.write( "2500+14400=16900<BR>\n" );
document.write( "16900=16900\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );