document.write( "Question 1199411: A projectile is fired at an angle of 30° to the horizontal with a velocity of 40ms-1. Calculate the velocity attained after 1sec.(g=10ms-2? \n" ); document.write( "
Algebra.Com's Answer #833282 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "A projectile is fired at an angle of 30° to the horizontal with a velocity of 40 m/s.
\n" ); document.write( "Calculate the velocity attained after 1 sec.(g = 10 m/s2)
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document.write( "At the starting moment, vertical velocity component is  \"V%5Bvert%5D%280%29%5D\" = 40*sin(30°) = \"40%2A%281%2F2%29\" = 20 m/s.\r\n" );
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document.write( "The time to get the maximum height is  \"t%5Bh_max%5D\" = \"V%5Bvert%5D%280%29%2Fg\" = \"20%2F10\" = 2 seconds,\r\n" );
document.write( "under the given condition, so after 1 second the projectile is still moving up.\r\n" );
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document.write( "Vertical component of the velocity at t = 1 second is  \r\n" );
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document.write( "    \"V%5Bvert%5D%281%29\" = \"V%5Bvert%5D%280%29+-+g%2At\" = 20 - 10*1 = 10 m/s.\r\n" );
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document.write( "Horizontal component of the projectile is  \"V%5Bhor%5D\" = 40*cos(30°) = \"40%2A%28sqrt%283%29%2F2%29\" m/s\r\n" );
document.write( "remains constant during the entire flight (till hitting the ground). \r\n" );
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document.write( "Thus the velocity attained after 1 second is\r\n" );
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document.write( "      V(t=1) = \"sqrt%28%28V%5Bvert%5D%281%29%29%5E2+%2B+%28V%5Bhor%5D%29%5E2%29\" = \"sqrt%2810%5E2+%2B+%2840%2A%28sqrt%283%29%2F2%29%29%5E2%29\" = \"sqrt%28100+%2B+1200%29\" = \"sqrt%281300%29\" = 36.055 m/s.   ANSWER\r\n" );
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