document.write( "Question 1199402: Kory drives from Edmonton to Lloydminster and back. Going to Lloydminster, he drives with an average speed of 96 km/h. For the return trip, he averages a speed of 100 km/h. The total time driving is 5.1 hours. \n" ); document.write( "
Algebra.Com's Answer #833271 by josgarithmetic(39633)\"\" \"About 
You can put this solution on YOUR website!
You did not finish the problem description or did not write what question to answer. You can expect that the
\n" ); document.write( "distance is the same value in each direction.
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document.write( "                 SPEED         TIME           DISTANCE\r\n" );
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document.write( "GOING TO            96\r\n" );
document.write( "COMING BACK        100\r\n" );
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document.write( "TOTAL                           5.1\r\n" );
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\n" ); document.write( "\n" ); document.write( "You might continue:
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document.write( "                 SPEED         TIME           DISTANCE\r\n" );
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document.write( "GOING TO            96         5.1-x          96(5.1-x)\r\n" );
document.write( "COMING BACK        100          x            100x\r\n" );
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document.write( "TOTAL                           5.1\r\n" );
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\n" ); document.write( "\n" ); document.write( "You should understand that both directions being same length,
\n" ); document.write( "\"highlight_green%2896%285.1-x%29=100x%29\".\r
\n" ); document.write( "\n" ); document.write( "Solve for the time \"coming back\", and then evaluate time \"going to\" and the distance either direction.\r
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\n" ); document.write( "\n" ); document.write( "\"%2896%29%285.1%29-96x=100x\"
\n" ); document.write( "\"%2896%29%285.1%29=196x\"
\n" ); document.write( "\"x=%28%2896%29%285.1%29%29%2F196\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%2824%2F49%295.1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2.498\"\r
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\n" ); document.write( "\n" ); document.write( "GOING TO, 2.602 hours, or 2 hours 36 minutes
\n" ); document.write( "COMING BACK, 2.498 hours, or 2 hours 30 minutes\r
\n" ); document.write( "\n" ); document.write( "DISTANCE BETWEEN THE CITIES, 250 kilometers
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