document.write( "Question 1199402: Kory drives from Edmonton to Lloydminster and back. Going to Lloydminster, he drives with an average speed of 96 km/h. For the return trip, he averages a speed of 100 km/h. The total time driving is 5.1 hours. \n" ); document.write( "
Algebra.Com's Answer #833270 by greenestamps(13216) You can put this solution on YOUR website! \n" ); document.write( "Since you did not ask a question, I will assume we are supposed to determine the distance between Edmonton and Lloydminster. \n" ); document.write( "The distances are the same, and the ratio of the speeds is 96:100 = 24:25. That means the ratio of the times at the two speeds is 25:24. \n" ); document.write( "That means 25/49 of the total time is spent at the lower speed and 24/49 at the higher speed. \n" ); document.write( "25/49 of the total 5.1 hours is (25/49)(51/10)=1275/490=255/98 hours. \n" ); document.write( "The distance from Edmonton to Lloydminster is (255/98)(96)=249.8km to 1 decimal place. \n" ); document.write( " \n" ); document.write( " |