document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199383>Question 1199383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If log2 = a and log 3 = b , then express log 1.8 in terms of an and b? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #833237 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=833237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If log2 = a and log 3 = b , then express log 1.8 in terms of an and b?<BR>\n" );
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document.write( "Assuming common logs (base 10):<BR>\n" );
document.write( "1.8 = 3*3*2/10<BR>\n" );
document.write( "log(1.8) = log(3) + log(3) + log(2) - log(10)<BR>\n" );
document.write( "= b + b + a - 1<BR>\n" );
document.write( "= a + 2b - 1<BR>\n" );
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document.write( "If you don't like the 1, then<BR>\n" );
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