document.write( "Question 1199370: Find a and b.\r
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\n" ); document.write( "\n" ); document.write( "If | x + 2 | < 5, then a < x - 2 < b.\r
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\n" ); document.write( "\n" ); document.write( "Must I solve left side inequality first?\r
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\n" ); document.write( "\n" ); document.write( "If so, -5 < x + 2 < 5 is the set up.\r
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\n" ); document.write( "\n" ); document.write( "Subteact 2 from all sides.\r
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\n" ); document.write( "\n" ); document.write( "-5 - 2 < x < 5 - 2\r
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\n" ); document.write( "\n" ); document.write( "-7 < x < 3\r
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\n" ); document.write( "\n" ); document.write( "Is this correct? If correct, what is the next step?\r
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Algebra.Com's Answer #833235 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The jump from
\n" ); document.write( "|x+2| < 5
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\n" ); document.write( "-5 < x + 2 < 5
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\n" ); document.write( "\n" ); document.write( "The same can be said when you went from
\n" ); document.write( " -5 < x + 2 < 5
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\n" ); document.write( "-7 < x < 3\r
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\n" ); document.write( "\n" ); document.write( "Then, as the tutor @greenestamps has pointed out, you subtract 2 from all sides to get x-2 in the middle.
\n" ); document.write( "-7 < x < 3
\n" ); document.write( "-7-2 < x-2 < 3-2
\n" ); document.write( "-9 < x-2 < 1\r
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\n" ); document.write( "\n" ); document.write( "Or you can subtract 4 from all sides after the absolute value bars have been removed.\r
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\n" ); document.write( "\n" ); document.write( "Why 4?
\n" ); document.write( "Because we want to go from x+2 to x-2
\n" ); document.write( "The gap from +2 to -2 on the number line is 4 units.\r
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\n" ); document.write( "\n" ); document.write( "I.e.
\n" ); document.write( "x+2 to (x+2)-4 to x-2\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "-5 < x + 2 < 5
\n" ); document.write( "-5-4 < (x + 2)-4 < 5-4
\n" ); document.write( "-9 < x-2 < 1
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