document.write( "Question 1199336: Hi
\n" ); document.write( "Town x and town y are 560km apart. At 11am a van leaves x for y travelling at a constant speed. At the same time a bus leaves x for y travelling at a constant speed. The two pass each other at 1.20pm . The average speed of the van is 60km per hour faster than the bus.\r
\n" ); document.write( "\n" ); document.write( "Find the vans average speed. How far is the bus from x when it passes the van.
\n" ); document.write( "Thanks \n" ); document.write( "

Algebra.Com's Answer #833205 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Hi
\n" ); document.write( "Town x and town y are 560km apart. At 11am a van leaves x for y travelling at a constant speed. At the same time a bus leaves x for y travelling at a constant speed. The two pass each other at 1.20pm . The average speed of the van is 60km per hour faster than the bus.\r
\n" ); document.write( "\n" ); document.write( "Find the vans average speed. How far is the bus from x when it passes the van.
\n" ); document.write( "Thanks
\n" ); document.write( "

They can't PASS EACH OTHER if they leave the same location and are heading in the same direction. One must've left x heading to y, \r\n" );
document.write( "and the other, y heading to x.\r\n" );
document.write( "That way, van's speed would be 150 km/h, NOT 240 km/h as the other person claims.\r\n" );
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document.write( "With the van heading to y, at 150 km/h,  hours after leaving x, it would've covered \r\n" );
document.write( "This is where they pass each other, which is also the distance that the bus is, from x.\r\n" );
document.write( "OR\r\n" );
document.write( "Calculate the distance the bus traveled from y to the \"passing\" point, and then subtract that from 560 km. The result should be the same!

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