document.write( "Question 1198771: A random sample of 150 college students regarding their work schedules produce a
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document.write( "mean of 25.4 hours worked per week with a standard deviation of 12 hours.
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document.write( "a) What is the point estimate of mean time worked per week? Calculate margin of
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document.write( "error when α = 0.01.
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document.write( "b) Construct a 95% confidence interval for the mean number of hours worked per week
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document.write( "by college students \n" );
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Algebra.Com's Answer #833180 by Theo(13342)![]() ![]() You can put this solution on YOUR website! a) What is the point estimate of mean time worked per week? Calculate margin of \n" ); document.write( "error when α = 0.01.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the point estimate of the mean time worked per week is the mean of the sample which is equal to 25.4 hours worked per week.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the margin of error when alpha = .01 is found by using the t-score as follows: \n" ); document.write( "note that you are using the t-score rather than the z-score because the standard deviation is taken from the sample rather than from the population. \n" ); document.write( "t-score formula is: \n" ); document.write( "t = (x-m)/s \n" ); document.write( "t is the t-score \n" ); document.write( "x is the sample mean \n" ); document.write( "m is the population mean \n" ); document.write( "s is the standard error \n" ); document.write( "standard error = standard deviation / square root of sample size = 12/sqrt(150) = .9797958971. \n" ); document.write( "at two sided alpha of .01, the alpha on each side will be .01/2 = .005 \n" ); document.write( "at 149 degrees of freedom, the critical t-score will be plus or minus plus or minus 2.609227895. \n" ); document.write( "use the plus value in the t-score formula to find the margin of error. \n" ); document.write( "you will get: \n" ); document.write( "2.609227895 = (x - 25.4) / .9797958971. \n" ); document.write( "solve for x to get: \n" ); document.write( "x = 2.609227895 * .9797958971 + 25.4 = 27.95651079. \n" ); document.write( "subtract 25.4 from that to get margin of error = 2.556510786. \n" ); document.write( "that's your margin of error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) Construct a 95% confidence interval for the mean number of hours worked per week by college students.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "95% confidence interval will have an alpha tail on each end equal to .05/2 = .025. \n" ); document.write( "the critical t-score with 149 degrees of freedom will be plus or minus plus or minus 1.976013145. \n" ); document.write( "when t = 1.976013145, t-score formula becomes 1.976013145 = (x - 25.4) / .9797958971. \n" ); document.write( "solve for x to get: \n" ); document.write( "x = 1.976013145 * 1.976013145 + 25.4 = 27.33608957. \n" ); document.write( "when t = -1.976013145, t-score formula becomes -1.976013145 = (x - 25.4) / .9797958971. \n" ); document.write( "solve for x to get: \n" ); document.write( "x = -1.976013145 * 1.976013145 + 25.4 = 23.46391043. \n" ); document.write( "your 95% confidence interval is from 23.46391043 to 27.33608957.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i've checked this a few times and i'm pretty sure this is correct. \n" ); document.write( "let me know if you have any questions. \n" ); document.write( "theo \n" ); document.write( " |