document.write( "Question 1198714: In 2012, the population of a city was 5.62 million. The exponential growth rate was 2.41% per year.
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document.write( "a) Find the exponential growth function.
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document.write( "b) Estimate the population of the city in 2018.
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document.write( "c) When will the population of the city be 9million?
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document.write( "d) Find the doubling time.
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document.write( "I already asked this question but I need more Clarification \n" );
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Algebra.Com's Answer #833178 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula to use is f = p * (1+r) ^ n \n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the growth rate per time period \n" ); document.write( "(1+r) is the growth factor per time period \n" ); document.write( "n is the number of time periods \n" ); document.write( "p is equal to 5.62 \n" ); document.write( "r is equal to 2.41% / 100 = .0241 \n" ); document.write( "1+r is equal to 1.0241 \n" ); document.write( "n is equal to 2018 minus 2012 = 6 \n" ); document.write( "formula becomes f = 5.62 * (1+r) ^ 6 \n" ); document.write( "solve for f to get f = 6.483216317. \n" ); document.write( "answer to (a) ia f = p * (1+r) ^ n \n" ); document.write( "answer to (b) is 6.483216317 \n" ); document.write( "answers to c and d are shown below. \n" ); document.write( "c) When will the population of the city be 9 million? \n" ); document.write( "to find this, replace f with 9 in the equation to solve for b and replace 6 with n to get: \n" ); document.write( "9 = 5.62 * 1.0241 ^ n \n" ); document.write( "divide both sides of the equation by 5.62 to get: \n" ); document.write( "9/5.62 = 1.0241 ^ n \n" ); document.write( "take the natural log of both sides of the equation to get: \n" ); document.write( "ln(9/5.62) = ln(1.0241 ^ n) \n" ); document.write( "since ln(1.0241 ^ n) = n * ln(.0241), the equation becomes: \n" ); document.write( "ln(9/5.62) = n * ln(1.0241) \n" ); document.write( "divide both sides of the equation by ln(1.0241) to get: \n" ); document.write( "ln(9/5.62) / ln(1.0241) = n \n" ); document.write( "solve for n to get: \n" ); document.write( "n = 19.77363701 \n" ); document.write( "to confirm, replace n in the equation with that and solve for f to get: \n" ); document.write( "f = 5.62 * 1.0241 ^ 19.77363701 = 9, confirming the value of n is correct. \n" ); document.write( "since your base year is 2012, add 19.7763701 to that to get 2031.773637. \n" ); document.write( "that should be in the year sometime in the year 2031. \n" ); document.write( "d) Find the doubling time. \n" ); document.write( "to find the doubling time, multiply 5.62 * 2 to get 11.24 \n" ); document.write( "equation becomes 11.24 = 5.62 * 1.0241 ^ n \n" ); document.write( "divide both sides of the equation by 5.62 to get: \n" ); document.write( "2 = 1.0241 ^ n \n" ); document.write( "take natural log of both sides of the equation to get: \n" ); document.write( "ln(2) = ln(1.0241^n) \n" ); document.write( "since ln(1.0241^n) is equal to n * ln(1.0241), equation becomes: \n" ); document.write( "ln(2) = n * ln(1.0241) \n" ); document.write( "divide both sides of the equation by ln(1.0241) and solve for n to get: \n" ); document.write( "n = ln(2) / ln(1.0241) = 29.10649184 \n" ); document.write( "that's the number of years it will take for 5.62 to double. \n" ); document.write( "confirm by replacing n with that in the equation and solving for f to get: \n" ); document.write( "f = 5.62 * 1.0241 ^ 29.20619184 = 11.24, confirming the value of n is good. \n" ); document.write( "your solution is that it will take 29.20619184 years for the population to double.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation can be graphed as shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "i'm not sure if this is going to help you, but i thought i would give it a try. \n" ); document.write( "let me know if you have any questions. \n" ); document.write( "theo\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |