document.write( "Question 1199330: Find the area of the larger circle in \"+cm%5E2+\" if \"+r=sqrt%282%29+\" cm.
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Algebra.Com's Answer #833164 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "To find the area of the larger circle, we need to find its radius.\r\n" );
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document.write( "The red and green triangles are similar 45-45-90 isosceles right triangles.\r\n" );
document.write( "Since the green hypotenuse is given to be \"sqrt%282%29\", it is a standard\r\n" );
document.write( "1-1-\"sqrt%282%29\" isosceles right triangle, and its legs are 1 each.\r\n" );
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document.write( "The radius of the larger circle is the sum of the red and green hypotenuses.\r\n" );
document.write( "The green hypotenuse is \"sqrt%282%29\" and is a radius of the small circle, So, the \r\n" );
document.write( "vertical red side is also \"sqrt%282%29\", because it is also a radius of the smaller circle. \r\n" );
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document.write( "We set up a proportion between the sides of the two similar triangles:\r\n" );
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document.write( "\"matrix%281%2C2%2Cgreen%2Chypotenuse%29%2Fmatrix%281%2C2%2Cred%2Chypotenuse%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cgreen%2Cvertical%2Cside%29%2Fmatrix%281%2C3%2Cred%2Cvertical%2Cside%29\"\r\n" );
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document.write( "\"sqrt%282%29%2Fmatrix%281%2C2%2Cred%2Chypotenuse%29\"\"%22%22=%22%22\"\"1%2Fsqrt%282%29\"\r\n" );
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document.write( "Cross-multiply and get\r\n" );
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document.write( "\"matrix%281%2C2%2Cred%2Chypotenuse%29\"\"%22%22=%22%22\"\"2\"\r\n" );
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document.write( "\"matrix%281%2C4%2Cradius%2Cof%2Clarger%2Ccircle%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2Cred%2Chypotenuse%29\"\"%22%22%2B%22%22\"\"matrix%281%2C2%2Cgreen%2Chypotenuse%29\"\r\n" );
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document.write( "\"matrix%281%2C4%2Cradius%2Cof%2Clarger%2Ccircle%29\"\"%22%22=%22%22\"\"2\"\"%22%22%2B%22%22\"\"sqrt%282%29\"\r\n" );
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document.write( "Using \"Area\"\"%22%22=%22%22\"\"pi%2Aradius%5E2\",\r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"pi%282%2Bsqrt%282%29%29%5E2\" cm2\r\n" );
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document.write( "Edwin
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