document.write( "Question 1199315: A father is 27 years older than his son ten years ago he was twice as old as his son how old is the father \n" ); document.write( "
Algebra.Com's Answer #833136 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "A father is 27 years older than his son. Ten years ago he was twice as old
\n" ); document.write( "as his son. How old is the father
\n" ); document.write( "~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "                    It can be solved mentally.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Ten years ago the father was 27 years older than his son AND twice as old as the son.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Hence, ten years ago the son was 27 years old, while the father was 2*27 = 54 years old.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It means that NOW the father is 54 + 10 = 64 years old.    ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved (mentally).\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );