document.write( "Question 1199312: let O(0,0), A(6,0), B(6,6), c(0,6) be the vertices of a square OABC, and Let M be the midpoint of OB. Find the probability that a point chosen at random from the square is
\n" ); document.write( "a) father from O than from M
\n" ); document.write( "b) more than twice as far from O as from M
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Algebra.Com's Answer #833134 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "let O(0,0), A(6,0), B(6,6), c(0,6) be the vertices of a square OABC, and Let M be the midpoint of OB.

\n" ); document.write( "Here is a sketch:
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\n" ); document.write( "a) Find the probability that a point chosen at random from the square is farther from O than from M.

\n" ); document.write( "To do this, determine where the points are that are the same distance from O as they are from M. This is simple; they lie on the perpendicular bisector of segment OM.

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\n" ); document.write( "Note that this result can be obtained algebraically by solving the equation that says the distance from P(x,y) to O(0,0) is the same as the distance from P(x,y) to M(3,3):

\n" ); document.write( "\"sqrt%28x%5E2%2By%5E2%29=sqrt%28%28x-3%29%5E2%2B%28y-3%29%5E2%29\"

\n" ); document.write( "(I won't do that in my response; however, it would be a good exercise for the student to solve this equation and find that indeed the set of points equidistant from O and M are the points on the line x+y=3.)

\n" ); document.write( "It should be easy to see from the sketch that the points in the square that are farther from O than from M constitute exactly 7/8 of the square. So

\n" ); document.write( "ANSWER to part a): 7/8

\n" ); document.write( "b) Find the probability that a point chosen at random from the square is more than twice as far from O as from M.

\n" ); document.write( "To solve this part, we could find the points that are EXACTLY twice as far from O as from M by solving the equation

\n" ); document.write( "\"sqrt%28x%5E2%2By%5E2%29=2%2A%28sqrt%28%28x-3%29%5E2%2B%28y-3%29%5E2%29%29\"

\n" ); document.write( "(Again I won't do that here in my response; and again it would be a good exercise for the student to do so. You should find that the circle is centered at (4,4) with radius 2*sqrt(2).)

\n" ); document.write( "The set of points exactly twice as far from O as from M is a circle. Two of those points are (2,2) and (6,6); and by symmetry the segment joining those two points is a diameter of the circle.

\n" ); document.write( "Here is a sketch:
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\n" ); document.write( "To answer this part of the problem, we need to find what fraction of the square is inside the circle.

\n" ); document.write( "The region of the square inside the circle consists of a semicircle plus an isosceles right triangle determined by the segment from (6,2) to (2,6). The radius of the circle is \"2%2Asqrt%282%29%29\" and the lengths of the legs of the triangle are 4, so the area of the semicircle is \"%281%2F2%29%28pi%29%28%282%2Asqrt%282%29%29%5E2%29=4pi\" and the area of the triangle is \"%281%2F2%29%284%29%284%29=8\".

\n" ); document.write( "The area of the whole square is 36, so the probability that a random point in the square is more than twice as far from O as it is from M is

\n" ); document.write( "ANSWER to part b): \"%284pi%2B8%29%2F36=%28pi%2B2%29%2F9\"
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