document.write( "Question 1199194: James spent $6780 on some watches and clocks. The amount spent on watches was $2820 more than the amount spent on the clocks. He bought 3/5 as many clocks as watches. Each clock cost $25 less than each watch. What was the total number of watches and clocks bought by James?\r
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Algebra.Com's Answer #833116 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "James spent $6780 on some watches and clocks.
\n" ); document.write( "The amount spent on watches was $2820 more than the amount spent on the clocks.
\n" ); document.write( "He bought 3/5 as many clocks as watches.
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\n" ); document.write( "What was the total number of watches and clocks bought by James?
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\n" ); document.write( "\n" ); document.write( "        The solution consists of two parts (two steps) and uses
\n" ); document.write( "        two clear simple ideas, accompanying with short calculations.\r
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\n" ); document.write( "\n" ); document.write( "                                First step\r
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document.write( "Let X be the amount of money spent on watches, Y be the amount of money spent on clocks.\r\n" );
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document.write( "From the condition, we have two equations\r\n" );
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document.write( "    X + Y = 6780     (total dollars)\r\n" );
document.write( "    X - Y = 2820     (X is $2820 more than Y)\r\n" );
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document.write( "To find X, add the equations. You will get  2X = 6780+2820 = 9600,  X = 9600/2 = 4800 dollars.\r\n" );
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document.write( "To find Y, subtract second equation from the first one. You will get  2Y = 6780-2820 = 3960,  Y = 3960/2 = 1980 dollars.\r\n" );
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\n" ); document.write( "\n" ); document.write( "First step is complete.  We just found that the amount spent on watches was  $4800;  the amount spent on clocks was  $1980.\r
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\n" ); document.write( "\n" ); document.write( "                                Second step\r
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document.write( "Let W be the number of watches bought by James.\r\n" );
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document.write( "Then the number of clocks was  \"%283%2F5%29W\" = 0.6W.\r\n" );
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document.write( "Each watch price was  \"4800%2FW\"  dollars;  each clock price was  \"1980%2F%280.6%2AW%29\" = \"3300%2FW\".\r\n" );
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document.write( "Next, the difference of prices is 25 dollars.  It gives this \"price\" equation\r\n" );
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document.write( "    \"4800%2FW\" - \"3300%2FW\" = 25.\r\n" );
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document.write( "Simplify and find W\r\n" );
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document.write( "    \"1500%2FW\" = 25\r\n" );
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document.write( "    W = \"1500%2F25\" = 60.\r\n" );
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document.write( "ANSWER.  60 watches and  \"%283%2F5%29%2A60\" = 36 clocks.\r\n" );
document.write( "         The total number of items was 60+36 = 96.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The meaning of this problem is not to make tons of calculations.\r
\n" ); document.write( "\n" ); document.write( "The meaning is to find a right idea of solution.\r
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