document.write( "Question 1199298: A first number plus twice a second number is 13. Twice the first number plus the second totals 32. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #833108 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let first number be \"x\" and second number \"y\" \r
\n" ); document.write( "\n" ); document.write( "if a first number plus twice a second number is \"13\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2y=13\" ..........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=13-2y\" ........eq.1\r
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\n" ); document.write( "\n" ); document.write( "if twice the first number plus the second totals \"32\", we have \r
\n" ); document.write( "\n" ); document.write( "\"2x%2By=32\"..........eq.2, substitute \"x\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"2%2813-2y%29%2By=32\"\r
\n" ); document.write( "\n" ); document.write( "\"26-4y%2By=32\"\r
\n" ); document.write( "\n" ); document.write( "\"26-3y=32\"\r
\n" ); document.write( "\n" ); document.write( "\"26-32=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"-6=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-2\"\r
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\n" ); document.write( "\n" ); document.write( "go to\r
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\n" ); document.write( "\n" ); document.write( "\"x=13-2y\" ........eq.1, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=13-2%28-2%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x=13%2B4\" \r
\n" ); document.write( "\n" ); document.write( "\"x=17\" \r
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\n" ); document.write( "\n" ); document.write( "the numbers are:\"17\" ,\"-2\"\r
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