document.write( "Question 1199254: An administrator at a Midwest university estimates that 12% of the female college students in a
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document.write( "P.A. program will change their major to a D.O. program. A random sample of 100 female P.A.
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document.write( "majors found that 9.5% had changed their major to a D.O. program. At α = 0.05, is there enough
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document.write( "evidence to reject the claim? Complete the hypotheses H1, a summary of your answer, and draw
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document.write( "the normal curve. \n" );
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Algebra.Com's Answer #833038 by Theo(13342)![]() ![]() You can put this solution on YOUR website! p = .12 \n" ); document.write( "q = 1 - p = .88 \n" ); document.write( "sample size = 100 \n" ); document.write( "standard error = sqrt(p * q / 100) = sqrt(.12*.88/100) = .0325 rounded to 4 decimal places. \n" ); document.write( "z-score = (.095 - .12) / .0325 = -.769 rounded to 3 decimal places. \n" ); document.write( "area to the left of that z-score = .2209 rounded to 4 decimal places. \n" ); document.write( "that's your test alpha. \n" ); document.write( "the two tailed critical alpha is .05/2 = .025 on each end. \n" ); document.write( "the test alpha is greater than this, therefore the results are not significant. \n" ); document.write( "the conclusion is that there is not enough evidence to support the claim that the percentage is not 12%. \n" ); document.write( "H0 states that the percentage is 12% \n" ); document.write( "H1 states that the percentage is not 12%. \n" ); document.write( "the z-score curve looks like the following: \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |