Algebra.Com's Answer #833004 by MathTherapy(10858)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
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document.write( "If tan 𝛼 = − 12/35 and cot 𝛽 = 3/4
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document.write( " for a second-quadrant angle 𝛼 and a third-quadrant angle 𝛽, find the following.
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document.write( "(a) sin(𝛼 + 𝛽)
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document.write( "(c) tan(𝛼 + 𝛽)
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document.write( "Pay no attention to what that NUT is trying to \"sell\" you! It's nothing but sheer RUBBISH! Is she ever going to learn?\r\n" );
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document.write( "You may have noticed the following:\r\n" );
document.write( "1) Length of the hypotenuse can NEVER be negative.\r\n" );
document.write( "2)  , which is NOT  , as that person suggests. And, As a matter\r\n" );
document.write( "of fact, this calculates to 0, although presented in a RIDICULOUS manner ( ), instead of  , etc.\r\n" );
document.write( "Why would someone have 0 as a denominator? Is that EVER permissible? Some of the things I see on here are as dumb as things can ever be!\r\n" );
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document.write( "If you want correct answers, then read on! \r\n" );
document.write( "Required: sin (𝛼 + 𝛽), and: sin (𝛼 + 𝛽) = sin 𝛼 cos 𝛽 + cos 𝛼 sin 𝛽 \r\n" );
document.write( ". We can see that sin 𝛼, cos 𝛼, sin 𝛽 and cos 𝛽 are needed.\r\n" );
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document.write( "Given:  in the 2nd Quadrant\r\n" );
document.write( "This is one of the Pytahorean Triples, of the form: 12-35-37. Therefore, hypotenuse = r = 37.\r\n" );
document.write( "We therefore get:  \r\n" );
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document.write( " Given:  in the 3rd Quadrant\r\n" );
document.write( "This is one of the Pytahorean Triples, of the form: 3-4-5. Therefore, hypotenuse = r = 5.\r\n" );
document.write( "We therefore get:  \r\n" );
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document.write( "So, sin (𝛼 + 𝛽) = sin 𝛼 cos 𝛽 + cos 𝛼 sin 𝛽 \r\n" );
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document.write( "So, cos (𝛼 + 𝛽) = cos 𝛼 cos 𝛽 - sin 𝛼 sin 𝛽 \r\n" );
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