document.write( "Question 1199231: A positive real number is 2 less than another. If the sum of the squares of the two numbers is 6, find the numbers. \n" ); document.write( "

Algebra.Com's Answer #833002 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "Let x be the smaller positive real number.\r\n" );
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document.write( "Then the larger number is (x+2), and the problem leads to equation\r\n" );
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document.write( "    x^2 + (x+2)^2 = 6    (the sum of squares is 6).\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    x^2 + (x^2 + 4x + 4) = 6\r\n" );
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document.write( "    2x^2 + 4x -2 = 0\r\n" );
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document.write( "     x^2 + 2x - 1 = 0\r\n" );
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document.write( "Use the quadratic formula\r\n" );
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document.write( "      =  =  = .\r\n" );
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document.write( "ANSWER.  The numbers are  x =   (the positive root) and .\r\n" );
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