document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17270>Question 17270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the slope if the line is -1/2 and it passes through the point (1,2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8330 by </B><A HREF=/tutors/aboutme.mpl?userid=plourde216><B>plourde216(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=plourde216><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When you are given the slope of a line and a point that is on the line, you should use point-slope form. Point-slope form is (y-y1)=m(x-x1). The m stands for slope, x1 and y1 are the values from the ordered pair that you are give. In this case, the formula would read (y-2)=(-1/2)(x-1). Your next step would be to distribute the -1/2 to (x-1). This will leave you with (-1/2)x + (1/2) on the right side of the equation.<BR>\n" );
document.write( "y-2=(-1/2)x + (1/2)<BR>\n" );
document.write( "Now you will add 2 to both sides in order to get y by itself.<BR>\n" );
document.write( "y=(-1/2)x +(5/2)\r<BR>\n" );
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document.write( "Hope this helps </SPAN>\n" );
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