document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198774>Question 1198774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The maintenance department at the main campus of a large state university receives daily requests to replace fluorecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 42 and a standard deviation of 3. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 39 and 42? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832993 by </B><A HREF=/tutors/aboutme.mpl?userid=Shin123><B>Shin123(626)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shin123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shin123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 39 is 1 standard deviation away from the mean. By the 68-95-99.7 rule, approximately 68% of the number of light bulb replacement requests are between 39 and 45. Since the bell-shaped distribution is symmetrical around the mean, 34% of the number of light bulb replacement requests are between 39 and 42. </SPAN>\n" );
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