document.write( "Question 1199210: If \"+a%5E2b%5E3c%5E4=648000+\", where a, b and c are distinct positive integers greater than 1, what is the least possible value of a+b+c? \n" ); document.write( "
Algebra.Com's Answer #832967 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Prime factorization:
\n" ); document.write( "648000 = 2^6*3^4*5^3\r
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\n" ); document.write( "\n" ); document.write( "Then rewrite the expression a bit.
\n" ); document.write( "648000 = 2^6*3^4*5^3
\n" ); document.write( "648000 = (2^3)^2*5^3*3^4
\n" ); document.write( "648000 = 8^2*5^3*3^4
\n" ); document.write( "It fits the format a^2*b^3*c^4 such that
\n" ); document.write( "a = 8
\n" ); document.write( "b = 5
\n" ); document.write( "c = 3
\n" ); document.write( "So a+b+c = 8+5+3 = 16\r
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\n" ); document.write( "\n" ); document.write( "We can do a bit of rearranging like this
\n" ); document.write( "648000 = 2^6*3^4*5^3
\n" ); document.write( "648000 = 2^4*2^2*3^4*5^3
\n" ); document.write( "648000 = 2^4*(2*3^2)^2*5^3
\n" ); document.write( "648000 = 2^4*18^2*5^3
\n" ); document.write( "648000 = 18^2*5^3*2^4
\n" ); document.write( "Showing that
\n" ); document.write( "a+b+c = 18+5+2 = 25
\n" ); document.write( "which isn't smaller than the previous result (16) we computed.\r
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\n" ); document.write( "\n" ); document.write( "Or we could do this
\n" ); document.write( "648000 = 2^6*3^4*5^3
\n" ); document.write( "648000 = 2^2*2^4*3^4*5^3
\n" ); document.write( "648000 = 2^2*(2*3)^4*5^3
\n" ); document.write( "648000 = 2^2*6^4*5^3
\n" ); document.write( "648000 = 2^2*5^3*6^4
\n" ); document.write( "So,
\n" ); document.write( "a+b+c = 2+5+6 = 13
\n" ); document.write( "which is smaller than the 16 computed earlier.\r
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\n" ); document.write( "\n" ); document.write( "I used computer software to do a brute-force search of all possible triples a,b,c from 2 to 100. Those are the only three possible sums I could find. There may be others.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 13
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