document.write( "Question 1199182: Find the area of region ABCD in cm^2 if the radius of the circle is 2 cm and both AB and CD are perpendicular to EF.
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Algebra.Com's Answer #832932 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Also using Edwin's figure....

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\n" ); document.write( "OD is the radius, and OF is half the radius; that makes each of the four triangles in the figure 30-60-90 right triangles. That means all six central angles are 60 degrees, so

\n" ); document.write( "(1) The two circular sectors AOD and BOC are each one-sixth of the circle; together their areas are one-third the area of the circle, which is \"%284%2F3%29pi\"; and
\n" ); document.write( "(2) each of the two triangular regions AOB and COD is a triangle with base \"2sqrt%283%29\" and height 1; together their areas are \"2sqrt%283%29\".

\n" ); document.write( "So the area of region ABCD is

\n" ); document.write( "ANSWER: \"%284%2F3%29pi%2B2sqrt%283%29\"

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