document.write( "Question 1199182: Find the area of region ABCD in cm^2 if the radius of the circle is 2 cm and both AB and CD are perpendicular to EF.
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Algebra.Com's Answer #832916 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "I will borrow the plot from the post by Edwin.\r\n" );
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document.write( "The area of the figure  ABCD  is the sum of \r\n" );
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document.write( "      the area of triangle AOB   + the area of triangle DOC + \r\n" );
document.write( "    + the area of the sector AOD + the area of the sector BOC.\r\n" );
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document.write( "The area of triangle AOB is the same as the area of equilateral triangle with the side of 2 units,\r\n" );
document.write( "so it is  =  square units.\r\n" );
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document.write( "The area of triangle AOB + the area of triangle DOC =  square units.\r\n" );
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document.write( "Next, the area of the sector AOD is    of the area of the circle with the radius of 2;\r\n" );
document.write( "so, the area of the sector AOD is   =  =  square units.\r\n" );
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document.write( "The area of the sector AOD + the area of the sector BOC is twice that value, i.e.    square units.\r\n" );
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document.write( "So, the    is    square units = 3.4641 + 4.1867 = 7.651 square units approximately.\r\n" );
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