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document.write( "Draw the two diameters AC and BD (in red) \r\n" );
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document.write( "OA is a radius so OA = 2. And by the marks along the horizontal diameter,\r\n" );
document.write( "OE is half a radius or half of 2 which is 1. So OE = 1\r\n" );
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document.write( "So triangle AOE is a 30-60-90 right triangle, so AE=
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document.write( "Triangle AOE has area = 

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document.write( "The four triangles AOE, BOE, COE, DOE are congruent. \r\n" );
document.write( "So the four of them have area
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document.write( "Next we find the area of the sector AOD.\r\n" );
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document.write( "Angle AOD is 60o because angles AOE and DOE are both 60o,\r\n" );
document.write( "so angle AOD = 180o-60o-60o = 60o.\r\n" );
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document.write( "The area of a sector is
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document.write( "and substituting the values, the area of sector AOD is\r\n" );
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document.write( "The sector BOC is congruent to the sector AOD\r\n" );
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document.write( "Adding the 4 triangles and the two sectors,\r\n" );
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document.write( "Area of ABCD = 
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document.write( "Edwin
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