document.write( "Question 17260: help.... I cant find the answer.\r
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document.write( "G= .067+.052 Log (M)\r
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document.write( "I tried subtracting .067 from both sides and got \r
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document.write( "G-.067 = .052 Log (M)
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document.write( " then dividing both sides by .052
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document.write( "to get (G-.067)/.052=Log M
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document.write( "then plugged it into my calculator and got the wrong answer. \n" );
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Algebra.Com's Answer #8329 by rapaljer(4671) You can put this solution on YOUR website! Are you solving for M? If so, you are correct so far. I think you might want to do two more steps. Rirst, the clear those decimals, multiply both numerator and denominator by 1000. That might look nicer: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next,suing the basic definition of logarithms: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As an alternative, if you did NOT multiply numerator and denominator by 1000, you would get this:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These answers should be the same. Do either of these look right?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |