document.write( "Question 17260: help.... I cant find the answer.\r
\n" ); document.write( "\n" ); document.write( "G= .067+.052 Log (M)\r
\n" ); document.write( "\n" ); document.write( "I tried subtracting .067 from both sides and got \r
\n" ); document.write( "\n" ); document.write( "G-.067 = .052 Log (M)
\n" ); document.write( " then dividing both sides by .052
\n" ); document.write( "to get (G-.067)/.052=Log M
\n" ); document.write( "then plugged it into my calculator and got the wrong answer.
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Algebra.Com's Answer #8329 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Are you solving for M? If so, you are correct so far. I think you might want to do two more steps. Rirst, the clear those decimals, multiply both numerator and denominator by 1000. That might look nicer:
\n" ); document.write( "\"%28G-.067%29%2F.052=log%2810%2CM%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+%281000G-67%29%2F52=log%2810%2CM%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Next,suing the basic definition of logarithms: \"+log%2810%2CM%29=+Y\" means \"10%5EY=M\"\r
\n" ); document.write( "\n" ); document.write( "\"10%5E%28%281000G-67%29%2F52%29+=+M++\"\r
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\n" ); document.write( "\n" ); document.write( "As an alternative, if you did NOT multiply numerator and denominator by 1000, you would get this:\r
\n" ); document.write( "\n" ); document.write( "\"10%5E%28%28G-.067%29%2F.052%29+=+M++\"\r
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\n" ); document.write( "\n" ); document.write( "These answers should be the same. Do either of these look right?\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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