document.write( "Question 1199176: A biologist has two brine solutions, one containing 2% salt and another containing 8% salt. How many milliliters of each solution should she mix to obtain 1 L of a solution that contains 5.6% salt?
\n" ); document.write( "2% solution mL
\n" ); document.write( "8% solution mL
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Algebra.Com's Answer #832893 by Theo(13342)\"\" \"About 
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x = the number of milliliters of 2% salt solution.
\n" ); document.write( "y = the number of milliliters of 8% salt solution.
\n" ); document.write( "total solution needs to be 1 liter = 1000 milliliters
\n" ); document.write( "your equations are:
\n" ); document.write( "x + y = 1000.
\n" ); document.write( ".02 * x + .08 * y = .056 * 1000 = 56
\n" ); document.write( "these two equations need to be solved simultaneously
\n" ); document.write( "multiply both sides of the first equation by .02 and leave the second equation as is to get:
\n" ); document.write( ".02 * x + .02 * y = 20
\n" ); document.write( ".02 * x + .08 * y = 56
\n" ); document.write( "subtract the first equation from the second to get:
\n" ); document.write( ".06 * y = 36
\n" ); document.write( "divide both sides of the equation by .06 to get:
\n" ); document.write( "y = 36 / .06
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 600
\n" ); document.write( "in the equation x + y = 1000, solve for x to get:
\n" ); document.write( "x = 400
\n" ); document.write( "when x = 400 and y = 600, .....
\n" ); document.write( "x + y = 400 + 600 = 1000
\n" ); document.write( ".02 * 400 + .08 * 600 = 56
\n" ); document.write( "56 / 1000 = .056
\n" ); document.write( "your solution is that 400 milliliters of 2% solution needs to be mixed with 600 milliliters of 8% solutopm to get 1000 milliliters = 1 liter of 5.6% solution.\r
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