document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199152>Question 1199152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> help a coffee shop manager to find the amount of a certain type of coffee that sells for $5 per kilogram which should be mixed with the 30kgs of another type of coffee which sells for $9 per kg in order to make a new flavor of coffee which she sells for $7 per kilogram </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832867 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The setup for a formal algebraic solution....<br><BR>\n" );
document.write( "(The cost of 30kg of coffee worth $9 per kg), plus (the cost of x kg of coffee worth $5 per kg), equals the cost of ((30+x) kg of coffee worth $7 per kg):<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%289%29+%2B+x%285%29+=+%2830%2Bx%29%287%29 ALIGN=MIDDLE  ALT=\"30%289%29+%2B+x%285%29+=+%2830%2Bx%29%287%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Solve using basic algebra....<br><BR>\n" );
document.write( "A quick, informal, common sense solution....<br><BR>\n" );
document.write( "The price per kg of the mixture is exactly halfway between the prices for the two kinds of coffee; that means the numbers of kg of the two kinds of coffee are the same.<br><BR>\n" );
document.write( "ANSWER: 30kg<br><BR>\n" );
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