document.write( "Question 1199151: Hi my question is :
\n" ); document.write( "An orange is spherical. Suppose it grows so that its volume increases at an average rate of
\n" ); document.write( "4cm3 /day.
\n" ); document.write( "a) Express the radius of the orange as a function of time t in days.
\n" ); document.write( "b) Determine the radius of the orange six weeks after it begins growing.
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Algebra.Com's Answer #832866 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
An orange is spherical.
\n" ); document.write( " Suppose it grows so that it's volume increases at an average rate of 4cm3/day.
\n" ); document.write( "a) Express the radius of the orange as a function of time t in days.
\n" ); document.write( " Volume of a sphere: V = \"%284%2F3%29%2Api%2Ar%5E3\"
\n" ); document.write( "let t = no. of growing days
\n" ); document.write( "\"%284%2F3%29%2Api%2Ar%5E3\" = 4t
\n" ); document.write( "Get rid of the denominator, multiply both sides by 3
\n" ); document.write( "\"4%2Api%2Ar%5E3\" = 12t
\n" ); document.write( "\"r%5E3\" = \"%2812t%29%2F%284%2Api%29\"
\n" ); document.write( "\"r%5E3\" = \"%283t%29%2F%28pi%29\"
\n" ); document.write( "r = \"%28%283t%29%2F%28pi%29%29%5E%281%2F3%29\"
\n" ); document.write( ":
\n" ); document.write( "b) Determine the radius of the orange six weeks after it begins growing.
\n" ); document.write( "r = \"%28%284%2A6%29%2F%28pi%29%29%5E%281%2F3%29\"
\n" ); document.write( "r = \"%2818%2F%28pi%29%29%5E%281%2F3%29\"
\n" ); document.write( "r = \"5.73%5E%281%2F3%29\"
\n" ); document.write( "r = 1.79 cm after 6 weeks
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