document.write( "Question 1199134: Show that the sum of the roots of a quadratic equation is -b/a.\r
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Algebra.Com's Answer #832847 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Method 1\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to see the two roots are \"x+=+%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29%29\" and \"x+=+%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "We can simplify things down a bit to say the two roots are \"x+=+%28-b%2BS%29%2F%282a%29%29\" and \"x+=+%28-b-S%29%2F%282a%29%29\" where \"S+=+sqrt%28b%5E2-4ac%29\"
\n" ); document.write( "When adding those roots together, the \"S\" terms cancel (since we have a positive S added to a negative S).\r
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\n" ); document.write( "\n" ); document.write( "We'll then have \"%28-b%2B%28-b%29%29%2F%282a%29+=+%28-2b%29%2F%282a%29+=+-b%2Fa\" as the sum of the two roots, where 'a' is nonzero.\r
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\n" ); document.write( "\n" ); document.write( "Method 2\r
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\n" ); document.write( "\n" ); document.write( "The vertex is located at the point (h,k)
\n" ); document.write( "The formula for h is
\n" ); document.write( "\"h+=+-b%2F%282a%29\"
\n" ); document.write( "where 'a' is nonzero.
\n" ); document.write( "This formula is useful for completing the square to get the equation \"y+=+ax%5E2%2Bbx%2Bc\" into vertex form \"y+=+a%28x-h%29%5E2%2Bk\"\r
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\n" ); document.write( "\n" ); document.write( "The equation \"x+=+h\" represents the vertical line through the vertex.
\n" ); document.write( "This vertical line is known as the axis of symmetry.\r
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\n" ); document.write( "\n" ); document.write( "Let the two roots be p and q.
\n" ); document.write( "If we knew the roots, we can average them to determine the value of h.
\n" ); document.write( "We'll use this fact to isolate \"p%2Bq\".\r
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\n" ); document.write( "\n" ); document.write( "\"h+=+%28p%2Bq%29%2F2\" .... h is the midpoint of p and q\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Ah+=+p%2Bq\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+2%2Ah\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+2%2A%28-b%2F%282a%29%29\" .... plug in h = -b/(2a)\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+-b%2Fa\"\r
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\n" ); document.write( "\n" ); document.write( "Method 3\r
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\n" ); document.write( "\n" ); document.write( "p and q are the roots of \"y+=+ax%5E2%2Bbx%2Bc\"\r
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\n" ); document.write( "\n" ); document.write( "Meaning:
\n" ); document.write( "\"ap%5E2%2Bbp%2Bc+=+0\"
\n" ); document.write( "and
\n" ); document.write( "\"aq%5E2%2Bbq%2Bc+=+0\"
\n" ); document.write( "Each input (x = p and x = q) lead to an output of y = 0.
\n" ); document.write( "i.e. p and q are the x-intercepts on the parabola.\r
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\n" ); document.write( "\n" ); document.write( "Subtract the equations straight down
\n" ); document.write( "\"%28ap%5E2%2Bbp%2Bc%29+-+%28aq%5E2%2Bbq%2Bc%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"ap%5E2%2Bbp%2Bc+-+aq%5E2-bq-c+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28ap%5E2-aq%5E2%29+%2B+%28bp-bq%29+%2B+%28c-c%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%28p%5E2-q%5E2%29%2Bb%28p-q%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%28p-q%29%28p%2Bq%29%2Bb%28p-q%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28p-q%29%28++a%28p%2Bq%29%2Bb++%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "From that, either
\n" ); document.write( "\"p-q+=+0\", or
\n" ); document.write( "\"a%28p%2Bq%29%2Bb+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "If the first scenario is the case, then \"p-q+=+0\" leads to \"p+=+q\".
\n" ); document.write( "This isn't particularly useful.\r
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\n" ); document.write( "\n" ); document.write( "So we move onto the second scenario.
\n" ); document.write( "\"a%28p%2Bq%29%2Bb+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%28p%2Bq%29+=+-b\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+-b%2Fa\"
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