document.write( "Question 1199069: Men's heights are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches, while women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches.
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document.write( "(a) What percentage of men must duck when walking through a door that is 72 inches high? (3 marks)
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document.write( "(b) What percentage of women must duck when walking through a door that is 70 inches high? (3 marks)
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document.write( "(c) What door height would allow at least 95% of men to walk through the door without ducking? \n" );
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Algebra.Com's Answer #832791 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Men's heights are normally distributed with a mean of 69.0 inches and \n" ); document.write( "a standard deviation of 2.8 inches, while women's heights are normally distributed \n" ); document.write( "with a mean of 63.6 inches and a standard deviation of 2.5 inches. \n" ); document.write( "(a) What percentage of men must duck when walking through a door that is 72 inches high? \n" ); document.write( "(b) What percentage of women must duck when walking through a door that is 70 inches high? \n" ); document.write( "(c) What door height would allow at least 95% of men to walk through the door without ducking? \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) Every normal distribution curve is a bell shaped curve.\r\n" ); document.write( "\r\n" ); document.write( " In this problem, they want you determine the area under this specific normal curve\r\n" ); document.write( " on the right from the raw mark of 72 inches. This area is the sought probability.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Go to web-site https://onlinestatbook.com/2/calculators/normal_dist.html\r\n" ); document.write( " and find there free of charge online calculator, specially developed for this purpose.\r\n" ); document.write( "\r\n" ); document.write( " Input the mean value 69.0 and the standard deviation value 2.8;\r\n" ); document.write( " input 72 in the window \"Above\"; then click \"Recalculate\".\r\n" ); document.write( "\r\n" ); document.write( " You will get the ANSWER 0.142 in the window \"Probability\".\r\n" ); document.write( "\r\n" ); document.write( " The auxiliary plot will show you the area of the interest.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now, when you know \"what to do\", I will tell you that you can get the same result \r\n" ); document.write( " using your calculator TI-83 or TI-84 (or whatever).\r\n" ); document.write( "\r\n" ); document.write( " For it, use the calculator' standard function normalcdf with parameters\r\n" ); document.write( "\r\n" ); document.write( " z1 z2 mean SD \r\n" ); document.write( "\r\n" ); document.write( " P = normalcdf(72,9999,69.0,2.8) = 0.142.\r\n" ); document.write( "\r\n" ); document.write( " You will get the same value of the probability 0.142 from your calculator.\r\n" ); document.write( "\r\n" ); document.write( " At this point, the solution to part (a) is completed.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) For question (b), do THE SAME, changing your input numbers accordingly.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) In part (c), they want you determine the raw z-score in such a way, that the area \r\n" ); document.write( " under the normal curve on the left of this z-score would be 95% = 0.95.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " To do it, go to ANOTHER website https://onlinestatbook.com/2/calculators/inverse_normal_dist.html\r\n" ); document.write( " and find there ANOTHER free of charge online calculator, specially developed for this purpose.\r\n" ); document.write( "\r\n" ); document.write( " Input the mean value 0.95 in the window \"Area\"; input 69.0 in the window \"Mean\";\r\n" ); document.write( " input 2.8 in the window \"SD\" (standard deviation); then click \"Recalculate\".\r\n" ); document.write( "\r\n" ); document.write( " Click for the window \"Below\" as you want the area below 0.95;\r\n" ); document.write( " and finally click the button \"Recalculate\".\r\n" ); document.write( "\r\n" ); document.write( " You will get the ANSWER 73.6056, which represent the sought-for/(desired) z-score.\r\n" ); document.write( " (the height of the door in inches in this problem).\r\n" ); document.write( "\r\n" ); document.write( " The auxiliary plot will show you the area of the interest.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now, when you know \"what to do\", I will tell you that you can get the same result \r\n" ); document.write( " using your calculator TI-83 or TI-84 (or whatever).\r\n" ); document.write( "\r\n" ); document.write( " For it, use the calculator' standard function invNorm with parameters\r\n" ); document.write( "\r\n" ); document.write( " area mean SD \r\n" ); document.write( "\r\n" ); document.write( " P = invNorm(0.95,69.0,2.8) = 73.0056.\r\n" ); document.write( "\r\n" ); document.write( " You will get the same value 73.0056 for the z-score, which is the height of the door in inches \r\n" ); document.write( " in this problem.\r\n" ); document.write( "\r\n" ); document.write( " The auxiliary plot will show you the area of the interest.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " At this point, the solution to part (c) is completed.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more instructions on how to operate with your calculator, \n" ); document.write( "you may find instructions and descriptions in many web-sites in the Internet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |