document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1199073>Question 1199073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sprinkler is set in a corner of a rectangular lawn 10 feet by 25 feet. If the maximum distance the sprinkler can reach is ten feet, what percentage  of the lawn will be watered from this position? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832767 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let W = the width of the lawn = 25 ft<BR>\n" );
document.write( "Let L = the length of the lawn = 10 ft<BR>\n" );
document.write( "The sprinkler will cover one quadrant of a circle of radius = L<BR>\n" );
document.write( "The area of the sprinkler's coverage is pi*L^2/4<BR>\n" );
document.write( "The area of the rectangular lawn is W*L<BR>\n" );
document.write( "The fraction of the lawn covered by the sprinkler is pi*L^2/4/(W*L) = pi*L/(4*W)<BR>\n" );
document.write( "The percentage is therefore pi*10/(4*25)*100 = pi*10 = 31.4% </SPAN>\n" );
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