document.write( "Question 1199067: If f(3x/x-4) = x² + x + 1, what is the value of f(5)? \n" ); document.write( "
Algebra.Com's Answer #832764 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "If f(3x/x-4) = x² + x + 1, what is the value of f(5)?
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document.write( "To solve the problem, find the value of x such that\r\n" );
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document.write( "    \"%283x%29%2F%28x-4%29\" = 5.\r\n" );
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document.write( "It is easy: first, cross multiply to get\r\n" );
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document.write( "    3x = 5(x-4),\r\n" );
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document.write( "then simplify step by step\r\n" );
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document.write( "    3x = 5x - 20\r\n" );
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document.write( "    20 = 5x - 3x\r\n" );
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document.write( "    20 = 2x  --->  x = 20/2 = 10.\r\n" );
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document.write( "Now substitute x= 10 into the given formula. Since  \"%283x%29%2F%28x-4%29\" = 5 at  x= 10,  you will get then\r\n" );
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document.write( "    f(5) = \"10%5E2+%2B+10+%2B+1\" = 100 + 10 + 1 = 111.\r\n" );
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document.write( "ANSWER.  Under imposed conditions,  f(5) = 111.\r\n" );
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