document.write( "Question 1199062: Two crafty bacteria fall into a pot of milk which has recently been sterilized. They reproduce at a rate of 4% per day. Determine how many bacteria will be present after 100 days.\r
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document.write( "A. 100
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document.write( "B. 800
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document.write( "C. 0
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document.write( "D. 2
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document.write( "E. 109
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document.write( "F. 345 \n" );
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Algebra.Com's Answer #832745 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As the problem is posed, its meaning is dark,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "because the growth rate of 4% per day gives/keeps the population of 2 bacteria unchangeable in every next day, \n" ); document.write( "since the number of bacteria can only be integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the other side, the problem says that the growth rate is 4%, not zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The problem is badly posed in statistical sense, since the announced growth rate \n" ); document.write( "relation / (formula) does not work for so small initial number of bacteria.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " As the problem is posed, it is self-contradictory and, therefore, is  DEFECTIVE.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Alternatively, it can be a kind of an entertainment puzzles\r \n" ); document.write( "\n" ); document.write( " that are not Math problems, but are a kind of traps, instead.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |