document.write( "Question 1199026: Four years ago,a mother was 4 times as old as her son.In 4 years time, the sum of their ages will be 56years .Find the age of the mother when the son was born \n" ); document.write( "
Algebra.Com's Answer #832710 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = the son's age 4 years ago
\n" ); document.write( "4x = the mother's age 4 years ago\r
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\n" ); document.write( "\n" ); document.write( "Fast-forward 4 years to the present day
\n" ); document.write( "x+4 = the son's present age
\n" ); document.write( "4x+4 = the mother's present age\r
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\n" ); document.write( "\n" ); document.write( "Then fast-forward another 4 years
\n" ); document.write( "(x+4)+4 = x+8 = the son's age 4 years into the future
\n" ); document.write( "(4x+4)+4 = 4x+8 = the mother's age 4 years into the future\r
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\n" ); document.write( "\n" ); document.write( "These future ages add to 56
\n" ); document.write( "(x+8)+(4x+8) = 56
\n" ); document.write( "5x+16 = 56
\n" ); document.write( "5x = 56-16
\n" ); document.write( "5x = 40
\n" ); document.write( "x = 40/5
\n" ); document.write( "x = 8\r
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\n" ); document.write( "\n" ); document.write( "The son was 8 years old four years ago.
\n" ); document.write( "His mother was 4x = 4*8 = 32 years old four years ago.\r
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\n" ); document.write( "\n" ); document.write( "Fast-forward 8 years and the son and mother will be 8+8 = 16 and 32+8 = 40 respectively.
\n" ); document.write( "We can see that 16+40 = 56 to help confirm we have the correct ages.\r
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\n" ); document.write( "\n" ); document.write( "Since the son was 8 years old when she was 32, we can rewind 8 years to find that the mother was 32-8 = 24 years old when her son was born.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 24 years old
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