document.write( "Question 1199001: For the real-valued function f(x) and g(x) bellow find (f o g)(5).
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\n" ); document.write( "f(x)=2^(x-3) and g(x)= square root of (x^2+39)\r
\n" ); document.write( "\n" ); document.write( "The correct answer is one of the following. Which one is correct?\r
\n" ); document.write( "\n" ); document.write( "A) square root of 55\r
\n" ); document.write( "\n" ); document.write( "B) 32\r
\n" ); document.write( "\n" ); document.write( "C) 4\r
\n" ); document.write( "\n" ); document.write( "D) 8
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Algebra.Com's Answer #832687 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The notation (f o g)(x) is the same as f( g(x) ).\r
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\n" ); document.write( "\n" ); document.write( "To evaluate f( g(5) ), we first need the value of g(5).
\n" ); document.write( "\"g%28x%29+=+sqrt%28x%5E2%2B39%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%285%29+=+sqrt%285%5E2%2B39%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%285%29+=+sqrt%2825%2B39%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%285%29+=+sqrt%2864%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%285%29+=+8\"\r
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\n" ); document.write( "\n" ); document.write( "This means,
\n" ); document.write( "\"f%28g%285%29%29+=+f%288%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+2%5E%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%288%29+=+2%5E%288-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%288%29+=+2%5E%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%288%29+=+highlight%2832%29\"
\n" ); document.write( "and furthermore,
\n" ); document.write( "\"f%28g%285%29%29+=+%28f+o+g%29%285%29+=+highlight%2832%29\"
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