document.write( "Question 1199005: The figure below is a trapezium in which AB=40 cm, BC=25 cm, CD=12 cm and AD=17 cm. Calculate the area of the trapezium.
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Algebra.Com's Answer #832685 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is a sketch, showing altitudes DE and CF: \n" ); document.write( " \n" ); document.write( "The quick path to the answer is to guess that all the numbers in the problem are whole numbers. So look for Pythagorean triples. With AD=17, it is likely that AE is 8 and the altitude h is 15; and with the altitude 15, FB would be 20. And 8+12+20 = 40, as required. \n" ); document.write( "So the bases are 12 and 40, and the height is 15; the area is 15*((12+40)/2) = 15*26 = 390. \n" ); document.write( "ANSWER: 390 \n" ); document.write( "If you want a formal algebraic solution.... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( "I won't go through the whole process of solving that equation.... \n" ); document.write( "To solve it, isolate one of the square roots on one side of the equation and square both sides. That will leave you still with one square root; again isolate it and square both sides. Now you will have no square roots left; and the remaining equation can be solved for the altitude h with only mildly ugly arithmetic. \n" ); document.write( " \n" ); document.write( " |