document.write( "Question 1199005: The figure below is a trapezium in which AB=40 cm, BC=25 cm, CD=12 cm and AD=17 cm. Calculate the area of the trapezium.
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Algebra.Com's Answer #832685 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a sketch, showing altitudes DE and CF:

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\n" ); document.write( "The quick path to the answer is to guess that all the numbers in the problem are whole numbers. So look for Pythagorean triples. With AD=17, it is likely that AE is 8 and the altitude h is 15; and with the altitude 15, FB would be 20. And 8+12+20 = 40, as required.

\n" ); document.write( "So the bases are 12 and 40, and the height is 15; the area is 15*((12+40)/2) = 15*26 = 390.

\n" ); document.write( "ANSWER: 390

\n" ); document.write( "If you want a formal algebraic solution....

\n" ); document.write( "\"AE+=+sqrt%2817%5E2-h%5E2%29\"
\n" ); document.write( "\"FB+=+sqrt%2825%5E2-h%5E2%29\"

\n" ); document.write( "Then

\n" ); document.write( "\"sqrt%2817%5E2-h%5E2%29%2B12%2Bsqrt%2825%5E2-h%5E2%29=40\"

\n" ); document.write( "I won't go through the whole process of solving that equation....

\n" ); document.write( "To solve it, isolate one of the square roots on one side of the equation and square both sides. That will leave you still with one square root; again isolate it and square both sides. Now you will have no square roots left; and the remaining equation can be solved for the altitude h with only mildly ugly arithmetic.

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