document.write( "Question 1198967: Two 3 sided spinners are made with numbers 1 ,2,3 on each edge, each with an
\n" ); document.write( "equal probability of occuring. If the two spinners are spun ,probability of spinning a \r
\n" ); document.write( "\n" ); document.write( "Double 3
\n" ); document.write( "Any double
\n" ); document.write( "A total of five
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Algebra.Com's Answer #832659 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "1/3 is the probability of landing on \"3\" since there's one space we want out of 3 spaces total.
\n" ); document.write( "(1/3)*(1/3) = 1/9 is the probability of getting two \"3\"s in a row assuming each spin is independent of each other.\r
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\n" ); document.write( "\n" ); document.write( "1/9 also represents the probability of getting double \"1\"s for similar reasoning. Same goes for double \"2\"s
\n" ); document.write( "1/9 + 1/9 + 1/9 = 3/9 = 1/3 is the probability of any double.\r
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\n" ); document.write( "\n" ); document.write( "Here are the two ways to add to five
\n" ); document.write( "2+3 = 5
\n" ); document.write( "3+2 = 5
\n" ); document.write( "This is out of 3*3 = 9 ways to spin them.
\n" ); document.write( "Therefore, 2/9 is the probability of getting a sum of 5 of the two spins.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Double 3 has probability 1/9
\n" ); document.write( "Any double has probability 1/3
\n" ); document.write( "A total of five has probability 2/9
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