document.write( "Question 1198962: Lines drawn parallel to the base of the triangle pictured, separate the other two sides into 10 equally spaced parts. What percentage of the triangle is grey? \n" ); document.write( "
Algebra.Com's Answer #832653 by ikleyn(52781)\"\" \"About 
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document.write( "The area of the k-th triangle is  \"%28k%2F10%29%5E2\"  of the area of the greatest triangle, A.\r\n" );
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document.write( "Therefore, the area of k-th individual single shape is  \r\n" );
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document.write( "    \"%28k%2F10%29%5E2\" - \"%28%28k-1%29%2F10%29%5E2\"  of the area of greatest triangle, A,    (1)\r\n" );
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document.write( "or\r\n" );
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document.write( "    \"a%5Bk%5D\" = \"%281%2F100%29%2A%28k%5E2+-+%28k%5E2-2k%2B1%29%29%2AA\" = \"%281%2F100%29%282k-1%29%2AA\".    (2)\r\n" );
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document.write( "From here, the area of the grey part is\r\n" );
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document.write( "    A(grey) = \"%281%2F100%29%2A%281+%2B+5+%2B+9+%2B+13+%2B+17%29%2AA\" = \"%2845%2F100%29%2AA\".      (3)\r\n" );
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document.write( "(summing all (2k-1) over k = 1, 3, 5, 7, 9)\r\n" );
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document.write( "The area of the unshaded (white) part is\r\n" );
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document.write( "    A(white) = \"%281%2F100%29%2A%283+%2B+7+%2B+11+%2B+15+%2B+19%29\" = \"%2855%2F100%29%2AA\".    (4)\r\n" );
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document.write( "(summing all (2k-1) over k = 2, 4, 6, 8, 10)\r\n" );
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document.write( "Therefore,  the ratio under the problem's question is\r\n" );
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document.write( "    \"A%28grey%29%2FA%28white%29\" = \"45%2F55\" = \"9%2F11\".    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Surely, one can avoid calculating unshaded area (4), when the area of grey part (3) is just calculated.\r
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\n" ); document.write( "\n" ); document.write( "I did it only for the purpose of completeness.\r
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