Algebra.Com's Answer #832653 by ikleyn(52781)  You can put this solution on YOUR website! . \n" );
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document.write( "The area of the k-th triangle is of the area of the greatest triangle, A.\r\n" );
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document.write( "Therefore, the area of k-th individual single shape is \r\n" );
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document.write( " - of the area of greatest triangle, A, (1)\r\n" );
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document.write( "or\r\n" );
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document.write( " = = . (2)\r\n" );
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document.write( "From here, the area of the grey part is\r\n" );
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document.write( " A(grey) = = . (3)\r\n" );
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document.write( "(summing all (2k-1) over k = 1, 3, 5, 7, 9)\r\n" );
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document.write( "The area of the unshaded (white) part is\r\n" );
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document.write( " A(white) = = . (4)\r\n" );
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document.write( "(summing all (2k-1) over k = 2, 4, 6, 8, 10)\r\n" );
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document.write( "Therefore, the ratio under the problem's question is\r\n" );
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document.write( " = = . ANSWER\r\n" );
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document.write( "Solved.\r \n" );
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document.write( "------------\r \n" );
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document.write( "Surely, one can avoid calculating unshaded area (4), when the area of grey part (3) is just calculated.\r \n" );
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document.write( "I did it only for the purpose of completeness.\r \n" );
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